Question

14a.bc:81=a.bc

Answer 1

\(14a,bc:81=a,bc\)

\(\Rightarrow14a,bc:81\cdot100=a,bc\cdot100\)

\(\Rightarrow14a,bc:81=abc\)

\(\Rightarrow14000+abc=abc\cdot81\)

\(\Rightarrow abc\cdot80=14000\)

\(\Rightarrow abc=175\)

Hay a,bc = 1,75

Answer 2

Giup minh nha

Answer 3

14a,bc:81=a,bc

⇒14a,bc:81·100=a,bc·100

⇒14a,bc:81=abc

⇒14000+abc=abc·81

⇒abc·80=14000

Answer 4

14a,bc:81=a,bc

=>(14a,bc:81)*100=a,bc*100

=>14abc:81=abc

=>14000+abc=abc*81

=>abc*80=14000

=>abc=14000/80=175 hay a,bc=1,75