=1,4 x\(\dfrac{15}{49}-\) \(\left(\dfrac{4}{5}+\dfrac{2}{3}\right)\) : 2\(\dfrac{1}{5}\)
= \(\dfrac{3}{7}\) - \(\dfrac{22}{15}\) : \(\dfrac{11}{5}\)
= \(\dfrac{3}{7}\) - \(\dfrac{2}{3}\)
= \(-\dfrac{5}{21}\)
( 2\(\dfrac{1}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(x\)) = \(\dfrac{3}{4}\)
\(\dfrac{11}{5}\) + \(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\)
\(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\) - \(\dfrac{11}{5}\)
\(\dfrac{3}{5}\)\(x\) = - \(\dfrac{29}{20}\)
\(x\) = -\(\dfrac{29}{12}\)
3\(\dfrac{1}{3}\) x \(x+16\)\(\dfrac{3}{4}\)= 13,25
\(\dfrac{10}{3}\) x \(x\) + \(\dfrac{67}{4}\) = 13,25
\(\dfrac{10}{3}\) x \(x\) = 13,25 - \(\dfrac{67}{4}\)
\(\dfrac{10}{3}\times x=\) \(\dfrac{103}{28}\)
\(x\) = \(\dfrac{103}{28}:\dfrac{10}{3}\)
\(x=\) \(\dfrac{309}{280}\)
(2.4\(x\) - 36) : 1\(\dfrac{5}{7}\) = -1
(8\(x\) - 36): \(\dfrac{12}{7}\) = - 1
8\(x\) - 36 = - 1 \(\times\) \(\dfrac{12}{7}\)
8\(x\) - 36 = - \(\dfrac{12}{7}\)
8\(x\) = - \(\dfrac{12}{7}\) + 36
8\(x\) = \(\dfrac{240}{7}\)
\(x\) = \(\dfrac{30}{7}\)
=0,25 : (10,3 - 9,8 ) - \(\dfrac{3}{4}\)
=0,25 : 0,5 - 0,75
= 0,5 - 0,75
= -0,25
\(\left(3\dfrac{4}{5}-2\times x\right)\times1\dfrac{1}{3}=5\dfrac{5}{7}\)
\(\left(\dfrac{19}{5}-2\times x\right)\times\dfrac{4}{3}=\dfrac{40}{7}\)
\(\dfrac{19}{5}\times\dfrac{4}{3}-2\times x\times\dfrac{4}{3}=\dfrac{40}{7}\)
\(\dfrac{76}{15}-\dfrac{8}{3}x=\dfrac{40}{7}\)
\(\dfrac{8}{3}x=\dfrac{76}{15}-\dfrac{40}{7}\)
\(\dfrac{8}{3}x=\dfrac{-68}{105}\)
\(x=\dfrac{-68}{105}:\dfrac{8}{3}\)
\(x=\dfrac{-68}{105}\times\dfrac{3}{8}\)
\(x=\dfrac{-17}{70}\)
