Question

(1/3)^4.(-9/2)^6

Answer 1

`(1/3)^4 .(-9/2)^6`

`=[1^4]/[3^4].[9^6]/[2^6]`

`=1/[3^4].[(3^2)^6]/[2^6]`

`=[3^12]/[3^4]/[2^6]`

`=[3^8]/[2^6]`

`=6561/64`

Answer 2

= \(\dfrac{1}{81}\). \(\dfrac{531441}{64}\)

= \(\dfrac{6561}{64}\)

Answer 3

\(\left(\dfrac{1}{3}\right)^4\cdot\left(\dfrac{9}{2}\right)^6=\dfrac{1}{81}\cdot\dfrac{531 441}{64}=\dfrac{6561}{64}\)

Answer 4

\(=\dfrac{1}{81}.\dfrac{531441}{64}\\ =\dfrac{6561}{64}\)