Question

    (13/2020+23/2021+33/2022).(1/2-1/3-1/6)     Giupp toiii, dung thi toi tick nhe  

Answer 1

\(\left(\dfrac{13}{2020}+\dfrac{23}{2021}+\dfrac{33}{2022}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

= \(\left(\dfrac{13}{2020}+\dfrac{23}{2021}+\dfrac{33}{2022}\right).\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\)

= \(\left(\dfrac{13}{2020}+\dfrac{23}{2021}+\dfrac{33}{2022}\right).0\)

=\(0\)