\(\frac{\frac{1}{3}+\frac{1}{5}+\frac{1}{7}}{\frac{4}{3}+\frac{4}{5}+\frac{4}{7}}\)\(=\frac{\frac{1}{3}+\frac{1}{5}+\frac{1}{7}}{4.\left(\frac{1}{3}+\frac{1}{5}+\frac{1}{7}\right)}\)\(=\frac{1}{4}\)
\(\frac{\frac{1}{3}+\frac{1}{5}+\frac{1}{7}}{\frac{4}{3}+\frac{4}{5}+\frac{4}{7}}=\frac{\frac{1}{3}+\frac{1}{5}+\frac{1}{7}}{4x\left(\frac{1}{3}+\frac{1}{5}+\frac{1}{7}\right)}=\frac{1}{4}\)