A= 1/1.3+1/3.5+1/5.7+...+1/13.15
2A=2/1.3+2/3.5+2/5.7+...+2/13.15
2A=1-1/3+1/3-1/5+1/5-1/7+...+1/13-1/15
2A=1-1/15
2A=14/15
A=7/15
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Đặt \(A=\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+...+\frac{1}{195}\)
\(A=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{13.15}\)
\(A=\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\right)\)
\(A=\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\right)\)
\(A=\frac{1}{2}.\left(1-\frac{1}{15}\right)\)
\(A=\frac{1}{2}.\frac{14}{15}=\frac{7}{15}\)
\(A=\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+...+\frac{1}{195}\)
\(2A=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(2A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}\)
\(2A=1-\frac{1}{15}=\frac{14}{15}\)
\(A=\frac{14}{15}.\frac{1}{2}=\frac{7}{15}\)