Bài 13 :
\(n_{H2}=\dfrac{13,44}{22,4}=0,6\left(mol\right)\)
Pt : \(Zn+2HCl\rightarrow ZnCl_2+H_2|\)
1 2 1 1
0,6 1,2
\(n_{HCl}=\dfrac{0,6.2}{1}=1,2\left(mol\right)\)
\(m_{HCl}=1,2.36,5=43,8\left(g\right)\)
⇒ \(m_{tt\left(HCl\right)}=\dfrac{43,8.100}{80}=54,75\left(g\right)\)
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