a)Ta có: \(\frac{1}{3}+\frac{2}{3}:x=-7\)
\(\Rightarrow\frac{2}{3}:x=\left(-7\right)-\frac{1}{3}=\frac{-22}{3}\)
\(\Rightarrow x=\frac{2}{3}:\frac{-22}{3}=\frac{-1}{11}\)
c) Ta có:(2x-3).(6-2x) = 0
\(\Rightarrow\orbr{\begin{cases}2x-3=0\\6-2x=0\end{cases}\Rightarrow\orbr{\begin{cases}2x=3\\2x=6\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{3}{2}\\x=3\end{cases}}}\)
Vậy x = 2 hoặc x = \(\frac{3}{2}\)