-(12+x)+(-x-1)+(2x-3)=x-1
-12-x-x-1+2x-3=x-1
-12-2x-1+2x-3+x-1=0
-12+x-5=0
-12+x=5
x=-5/12
Vạy x=-5/12
-(12+x)+(-x-1)+(2x-3)=x-1
-12-x-x-1+2x-3=x-1
-12-2x-1+2x-3+x-1=0
-12+x-5=0
-12+x=5
x=-5/12
Vạy x=-5/12
x(2x-1)-4(x+1)=12+2x(x-3)
tìm x,biết
5.(x+7)-3.(2-x)
12(x-3)=5(x-1)+4
(-6).(x-7)+2(x+10)=x-18
7.(2x-1)-12(x-5)=3
|2x-1|=17
|8-3x|=14
tìm x,biết
5(x+7)-3(2-x)
12(x-3)=5(x-1)+4
(-6).(x-7)+2(x+10)=x-18
7(2x-1)-12(x-5)=3
|2x-1|=17
|8-3x|=14
2x+12=-3(-x) (6a+1) chia hey cho (3a-1) x+3 la uoc cua x-4 /2x+1/=2x+1
tìm số nguyên x
5/x+1+4/x+1=3/-13
-x+2+2x+3+x+1/4+2x+1/6=8/3
3/2x+1+10/4x+2-6/6x+2=12/26
giúp mình mik đang vội]
giải các bất phương trình sau và biểu diễn nghiệm trên trục số:
a)2x+2>4
b)3x+2.-5
c)10-2x>2
d)1-2x<3
e)10x+3-5x<=14x+12
f)(3x-1)<2x+4
g)4x-8>=3(2x-1)-2x+1
h)x^2-x(x+2)>3x-1
i)x+8>3x-1
j)3x-(2x+5)<=(2x-3)
k)(x-3)(x+3)<x(x+2)+3
l)2(3x-1)-2x<2x+1
m)3-2x/5>2-x/3
n)x-2/6-x-1/3<=x/2
o)x+1/3>2x-1/6-2
p)1+2x+1/3>2x-1/6-2
q)x+5/6-2x+1/3<=x+3/2
r)5x+4/6-2x-1/12>=4
Dạng 3: vận dụng các quy tắc: qt chuyển vế,qtdấu ngoặc, nhân phá ngoặc
a)3x –10 = 2x + 13
b) x + 12 = -5 –x
c) x + 5 = 10 –x
d)6x + 23= 2x –12
e) 12 –x = x + 1
f) 14 + 4x = 3x + 20
g) 2.(x-1) + 3(x-2) = x -4
h) 3.(4 –x) –2.( x-1) = x + 20
i) 4.( 2x + 7) –3.(3x –2) = 24
k) 3(x –2) + 2x = 10
van dung cac quy tac chuyen ve,quy tac dấu ngoặc,nhã phá ngoặc:
a, 3x-10=2x+13
b, x+12=-5-x
c, x+5=10-x
d,6x+2^3=2x-12
e,12-x=x+1
g, 2.(x-1)+3.(x-2)=x-4
f, 14+4x=3x+20
g, 2.(x-1)+3.(x-2)=x-4
f, 4.(2x+7)-3.(3x-2)=24
3(4-x)-2.(x-1)=x+20
3(x-2)+2x=10
1)a)2x-13=25+6x
b)12-x=3x+6
c)40-(25-2x)=x
d)|x-3|=5
e)|x-3|+(x+2)+(x+1)=12
2)tính
a)(-1).(-2).(-3).(-4).(-5).[(-3)-(-5)]
b)1-2+3-4+5-6+...-98+99
3)tim x
a)(x-1).(y-2)=5
b)x.(y-3)=12