Question

12\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

Answer 1

3down votefavorite 2

OK, this one has me stumped. Given that the solution for ax2+bx+c=0ax2+bx+c=0 x=−b±b2−4ac−−−−−−−√2a(∗)x=−b±b2−4ac2a(∗) How would you show using (∗)(∗) that x=−c/bx=−c/b when a=0a=0 (Please dont use a=0a=0 hence, bx+c=0bx+c=0.) có đúng không

Answer 2

vietsub đi bạn ơi ghi tiếng anh ko hỉu