Question

125%.\(\left(\dfrac{-1}{2}\right)^2\):\(\left(1\dfrac{5}{16}-1,5\right)\)+\(2018^0\)

Answer 1

\(125\%\cdot\left(-\dfrac{1}{2}\right)^2:\left(1\dfrac{5}{16}-1,5\right)+2018^0\)
\(=\dfrac{5}{4}\cdot\dfrac{1}{4}:\left(\dfrac{21}{16}-\dfrac{3}{2}\right)+1\)
\(=\dfrac{5}{16}:\left(-\dfrac{3}{16}\right)+1\)
\(=\dfrac{5}{16}\cdot\left(-\dfrac{16}{3}\right)+1\)
\(=-\dfrac{5}{3}+1\)
\(=-\dfrac{5}{3}+\dfrac{3}{3}\)
\(=-\dfrac{2}{3}\)

Answer 2

`125%*( (-1)/2 )^2 :(1 5/16 -1,5 )+2018^0`

`=1,25 * 1/4 :(21/16-3/2)+1`

`=1,25*1/4:(21/16-24/16)+1`

`=1,25*1/4:(-3)/16+1`

`=5/16*16/(-3)+1`

`=-5/3+1`

`=-5/3+3/3`

`=-2/3`

Answer 3

ngu