Đặt A=....
=>\(2A=2+2^2+2^3+...+2^{101}\)
\(2A-A=2^{101}-1\)
A=.....
Đặt A=....
=>\(2A=2+2^2+2^3+...+2^{101}\)
\(2A-A=2^{101}-1\)
A=.....
Đặt A=....
=>\(2A=2+2^2+2^3+...+2^{101}\)
\(2A-A=2^{101}-1\)
A=.....
Đặt A=....
=>\(2A=2+2^2+2^3+...+2^{101}\)
\(2A-A=2^{101}-1\)
A=.....
Đặt A=....
=>\(2A=2+2^2+2^3+...+2^{101}\)
\(2A-A=2^{101}-1\)
A=.....
Đặt A=....
=>\(2A=2+2^2+2^3+...+2^{101}\)
\(2A-A=2^{101}-1\)
A=.....
Tính
a) ( 100 -1^2 ) x ( 100 - 2^2 ) x ( 100 - 3^2 ) x ...x (100 - 19^2)
b ) ( 169 - 1^2 ) x ( 169 - 2^2 ) x ( 169 - 3^2 ) x ... x (100 - 19^2 )
Các bạn giúp mình nha thứ 6 mình phải nộp rồi
1, Tính \(\frac{1}{2}-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{1}{4}+\frac{2}{4}+\frac{3}{4}\right)-\left(\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}\right)+...+\left(\frac{1}{100}+\frac{2}{100}+\frac{3}{100}+...+\frac{99}{100}\right)\)2,Tính \(\left(1-\frac{1}{2^2}\right)x\left(1-\frac{1}{3^2}\right)x\left(1-\frac{1}{4^2}\right)x...x\left(1-\frac{1}{n^2}\right)\)
Bài 6 Tìm x
1) ( x+1 ) + ( x+2 ) + ( x+3 ) + ... + ( x+100 ) = 5750
2) ( 2x-1 ) + ( 4x-2 ) + ... + ( 200x - 100 ) = 5050
3) ( x+2 ) + ( x+4 ) + ( x+6 ) + ... + ( x + 100) = 2650
(\(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{100}}\)).x=\(\frac{2^{100}-1}{2^{100}}.100\)
Chứng minh A = 1 x 2-1 / 2 ! + 2 x 3- 1 / 3 ! + 3 x 4 -1 / 4 ! + ... 99 x 100 - 1 / 100 ! bé hơn 2
tìm x thuộc Z
a)1+2+3+.........+x=5050
b)1/2+1/6+........1x2+x=99/100
c)1/6+1/12+.......1/x2-x=59/100
d)x-2017+x-2016+.........+99+100=0
g)x-1+x-2+x-3+.......x-2017=0
(1-1/2^2) x (1-1/3^2) x ... x (1-1/100^2)
2016x(100-1^2)x(100-2^2)...(100-25^2)
1 x 2 + 2 x 3 + 3 x 4 + ... + 100 x 101 =
1 x 2 x 3 + 2 x 3 x 4 + ... + 100 x 101 x 102
Có cả lời giải nhé
1/Tìm x,biết:
a)x+(x+1)+(x+2)+(x+3)+...+(x+99)+(x+100)=5555
b)1+2+3+4+...+x=820
c)3(x+1)=9.27
d)x+2x+3x+...+99x+100x=15150
e)(x+1)+(x+2)+(x+3)+...+(x+100)=205550
f)3x+3x+1+3x+2=351