\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}=\dfrac{16}{32}+\dfrac{8}{32}+\dfrac{4}{32}+\dfrac{2}{32}+\dfrac{1}{32}=\dfrac{16+8+4+2+1}{32}=\dfrac{31}{32}\)
`1/2+1/4+1/8+1/16+1/32`
`= 1 - 1/2 + 1/2 - 1/4 + ... + 1/16 - 1/32`
`= 1 - 1/32`
` = 32/32 - 1/32`
` = 31/32`
1/2+1/4+1/8+1/16+1/32
=16/32+8/32+4/32+2/32+1/32=31/32