1+2-3-4+5+........................+197+198-199-200
=1+(2-3-4+5)+..........+(194-195-196+197)+(198-199-200)
=1+0+................+0+(-201)
=1+(-201)
=-200
1+2+3+4+5+6+7+8+9-1-2-3-4-5-6-7-8-9*1*2*3*4*5*6*7*8*9:1:2:3:4:5:6:7:8:9=???
1+1+1=6
2+2+2=6
3×3÷3=6
√4+√4+√4=6
5+5÷5=6
6×6÷6=6
7 ? 7 ? 7=6
8 ? 8 ? 8 =6
9 ? 9 ? 9=6
10 ? 10 ? 10=6
1+2+3+4+5+6+7+8+9+0.1.2.3.4.5.6.7.8.9.0.1-2-3-4-5-6-7-8-9-0=? ai tra loi nhanh va dung cho 1 tick
điền các kí hiệu toán học để hoàn thành bài toán
1 1 1 =6
2 2 2=6
3 3 3=6
4 4 4=6
5 5 5=6
6 6 6=6
7 7 7=6
8 8 8=6
9 9 9=6
10 10 10=6
Rút gọn biểu thức:
a) 4^5 . 9^4 - 2 . 6^9 / 2^10 . 3^8 + 6^8 .20
b)2 . 8^4 . 27^2 + 4 . 6^9 / 2^7 . 6^7 + 2^7 . 40 .9^4
5+5+8+0+6+4+5+2+4+1+1+2+3+4+5+6+6+7+8+9+100000000+45638+78536 x 12345 x 34 x 0 +100=
1+1=
2+2=
3+3=
4+4=
5+5=
6+6=
7+7=
8+8=
9+9=
Kết bạn nha mấy bạn
\(\left(6\right)\dfrac{3\sqrt{x}}{5\sqrt{x}-1}\le-3\)
\(\left(7\right)\dfrac{8\sqrt{x}+8}{6\sqrt{x}+9}>\dfrac{8}{3}\)
\(\left(8\right)\dfrac{\sqrt{x}-2}{2\sqrt{x}-3}< -4\)
\(\left(9\right)\dfrac{4\sqrt{x}+6}{5\sqrt{x}+7}\le-\dfrac{2}{3}\)
\(\left(10\right)\dfrac{6\sqrt{x}-2}{7\sqrt{x}-1}>-6\)
1+1+1+2+2+3+4+4+5+5+6+7+8+9
