\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}=\frac{125}{376}\)
=>\(3\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}\right)=3.\frac{125}{376}\)
=>\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{x\left(x+3\right)}=\frac{375}{376}\)
=>\(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{375}{376}\)
=>\(1-\frac{1}{x+3}=\frac{375}{376}\)
=>\(\frac{1}{x+3}=1-\frac{375}{376}\)
=>\(\frac{1}{x+3}=\frac{1}{376}\)
=>x+3=376
=>x=376-3
=>x=373
Vậy x=373
1/1+4 +1/4×7 +1/7×10+.....+1/x×(x+3)=16/49
