1/3+1/6+1/10+...+2/x(x+1)=1999/2000. ; b)2+2/3+2/6+2/12+...+2/x(x+1)=3980/1991
2+ 2/3 + 3/6 + 2/12 +...+ 2/x(x+1) = 3980/1991
2 + 2/3 +2/6 + 2/12+ .............+ 2/x(x + 1)= 3980/1991
Giup toi giai bai toan:
1+2/6+2/12+.....+2/x(x+1)=3980/1991
1+1\3+1/6+1/10+.............+2/x*(x+1)=1 1989/1991
Tìm x biết 1+1/3+1/6+1/10+...+2/x(x+1)=1/1991/1993
Tìm x biết 1+1/3+1/6+1/10+...+2/x(x+1)=1/1991/1993
1 + \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{10}\)
+......+ \(\dfrac{2}{x(x+1)}\) =1\(\dfrac{1989}{1991}\)
HeLp me
1 + \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{10}\) +...+ \(\dfrac{1}{x\left(x+1\right):2}\) = \(1\dfrac{1991}{1993}\)