Đề bài : \(\dfrac{11}{3}\times\left(\dfrac{1}{5}-\dfrac{1}{2}\right)\le x\le\dfrac{3}{11}\times\left(\dfrac{1}{5}+\dfrac{2}{3}-\dfrac{1}{2}\right)\)
\(\dfrac{11}{3}\times\left(\dfrac{1}{5}-\dfrac{1}{2}\right)=\dfrac{11}{3}\times\left(-\dfrac{3}{10}\right)\)\(=-\dfrac{33}{30}=-\dfrac{11}{10}\)
\(\dfrac{3}{11}\times\left(\dfrac{1}{5}+\dfrac{2}{3}-\dfrac{1}{2}\right)=\dfrac{3}{11}\times\dfrac{11}{30}=\dfrac{33}{330}=\dfrac{1}{10}\)
\(\Rightarrow\dfrac{-11}{10}\le x\le\dfrac{1}{10}\)
Vậy \(x\in\left\{-\dfrac{11}{10};-\dfrac{10}{10};-\dfrac{9}{10};-\dfrac{8}{10};-\dfrac{7}{10};-\dfrac{6}{10};-\dfrac{5}{10};-\dfrac{4}{10};-\dfrac{3}{10};-\dfrac{2}{10};-\dfrac{1}{10};0;\dfrac{1}{10}\right\}\)
