Question

11.[(2x-1^3)-1]+37=1401

X=bao nhiêu?

Answer 1

\(11\times\left[\left(2x-1^3\right)-1\right]+37=1401\)

\(11\times\left[\left(2x-1\right)-1\right]=1401-37\)

\(\left(2x-1\right)-1=1364\div11\)

\(2x-1=124+1\)

\(2x=125+1\)

\(2x=126\)

\(\Rightarrow x=63\)

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Answer 2

11[(2x-1³)-1]+37=1401

=> 11[(2x-1)-1]=1401-37

=> 11[(2x-1)-1]=1364

=> (2x-1)-1=1364:11

=> (2x-1)-1=124

=> 2x-1=124+1

=> 2x-1=125

=> 2x=125+1

=> 2x=126

=> x=126:2

=> x=63