Lời giải:
Gọi tổng trên là A
$2A=\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{101.102.103}$
$=\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+...+\frac{103-101}{101.102.103}$
$=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+....+\frac{1}{101.102}-\frac{1}{102.103}$
$=\frac{1}{1.2}-\frac{1}{102.103}=\frac{2626}{5253}$
$\Rightarrow A=\frac{1313}{5253}$