Question

1/1*2+1/2*3+1/3*4+1/4*5+...+1/99*100

Answer 1

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)

= \(=1-\frac{1}{100}\)

\(\frac{99}{100}\)