\(\dfrac{11}{12}x-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\\ =>\dfrac{11}{12}x-\dfrac{2}{5}-x=\dfrac{2}{3}\\ =\left(\dfrac{11}{12}-1\right)x-\dfrac{2}{5}=\dfrac{2}{3}\\ =>\left(\dfrac{11-12}{12}\right)x=\dfrac{2}{3}+\dfrac{2}{5}\\ =>\dfrac{-1}{12}x=\dfrac{2.5+2.3}{15}\\ =>-\dfrac{1}{12}x=\dfrac{16}{15}\\ =>x=\dfrac{16}{15}:\left(-\dfrac{1}{12}\right)\\ =>x=-\dfrac{64}{5}\)
Vậy \(x=-\dfrac{64}{5}\)
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