Question

(1/1*1/2+1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6)*10-x=0

Giải ra giúp mk nha mk tik

Answer 1

Làm như zậy bạn nhé ^_^"

Đặt :

\(A=\left(\frac{1}{1}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+\frac{1}{5}.\frac{1}{6}\right)\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{5.6}\)( mik lười viết bạn thông cảm nhé !!! )

\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)

\(A=\frac{1}{1}-\frac{1}{6}\)

\(A=\frac{5}{6}\)

Thay A vào biểu thức :

Ta có : \(\frac{5}{6}.10-x=0\)

=> \(\frac{25}{3}=x+0\)

=> \(x=\frac{25}{3}\)

Answer 2

(1/1*1/2+1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6)*10-x=0

=> (1/1.2+1/2.3+1/3.4+1/4.5+1/5.6)*10-x=0

=> (1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6)*10-x=0

=> (1-1/6)*10-x=0

=> 5/6*10-x=0

=> 25/3-x =0

=> x=0+25/3

=> x=25/3

Vậy x=25/3