Question

10.2^x-1+2^x+2=36

Answer 1

`10 . 2^(x - 1) + 2^(x+2)=36`

`=> 10  . 2^x . 2^(-1) + 2^x . 2^2 = 36`

`=> 10 . 2^x . 1/2 + 2^x . 4 = 36`

`=> 2^x . 5 + 2^x . 4 = 36`

`=> 2^x . (5+4)=36`

`=> 2^x . 9 = 36`

`=> 2^x = 36:9`

`=> 2^x=4`

`=> 2^x=2^2`

`=>x=2`

Vậy: `x=2`

Answer 2

\(10.2^{x-1}+2^{x+1}=36\)
\(10.2^{x-1}+2^{x-1+3}=36\)
\(10.2^{x-1}+2^{x-1}.2^3=36\)
\(2^{x-1}\left(10+2^3\right)=36\)
\(2^{x-1}\left(10+8\right)=36\)
\(2^{x-1}.18=36\)
\(2^{x-1}=36:18\)
\(2^{x-1}=2\)
\(x-1=1\)
\(x=1+1\)
\(x=2\)
Vậy \(x=2\)