Question

10101 x (\(\frac{5}{10101}\)_ \(\frac{5}{20202}\)+ \(\frac{5}{30303}\)+ \(\frac{5}{40404}\))

 

Answer 1

\(\frac{65}{12}\)nha bạn

Answer 2

\(10101\times\left(\frac{5}{10101}-\frac{5}{20202}+\frac{5}{30303}+\frac{5}{40404}\right)\)

\(=10101\times\left(\frac{10}{20202}-\frac{5}{20202}+\frac{20}{121212}+\frac{15}{121212}\right)\)

\(=10101\times\left(\frac{5}{20202}+\frac{25}{121212}\right)\)

\(=10101\times\frac{55}{121212}\)

\(=\frac{65}{12}\)

Answer 3

tô hoài an ơi sao mình thấy 20/121212+15/121212 lại bằng 25/121212 nhỉ?