\(-10-\left(x+5\right)+\left(3-x\right)=-8\)
\(\Leftrightarrow-10-x-5+3-x=-8\)
\(\Leftrightarrow-12-2x=-8\)
\(\Leftrightarrow2x=-4\)
\(\Leftrightarrow x=-2\)
-10 - (x + 5) + (3 - x) = -8
<=> -10 - x - 5 + 3 - x + 8 = 0
<=> (-x - x) - (10 + 5 - 3 - 8) = 0
<=> -2x -7 =0
<=> -2x = 7
<=> x = \(\frac{-7}{2}\)
Vậy x = \(\frac{-7}{2}\)
-10 - ( x + 5 ) + ( 3 - x ) = -8
-10-x-5+3-x=-8
(-10-5+3)-(x+x)=-8
-12-2x=-8
2x=-12-(-8)
2x=-4
x=-4:2
x=-2
vậy x=-2
nhớ k chô mình nhé
học tốt
=\(-10-\left(x+5\right)+\left(3-x\right)=-8\)
\(=-10-x-5+3-x=-8\)
\(=\left(-10-5+3\right)-x-x=-8\)
=\(-12-2x=-8\)
\(=-12-2x+8=0\)
\(-4-2x=0\)
\(=-2x=-4\)
\(x=\frac{-4}{-2}=2\)
\(-10-\left(x+5\right)+\left(3-x\right)=-8\)
\(-10-x-5+3-x=-8\)
\(-12-2x=-8\)
\(2x=-4\)
\(x=-2\)
Vậy\(x=-2\)
#DDN