`1 4/7 xx 3 4/11 xx 3 11/15 xx 5 5/8`
`= 11/7 xx 37/11 xx 56/15 xx 45/8`
`=111`
\(1\dfrac{4}{7}\cdot3\dfrac{4}{11}\cdot3\dfrac{11}{15}\cdot5\dfrac{5}{8}=\dfrac{11}{7}\cdot\dfrac{37}{11}\cdot\dfrac{56}{15}\cdot\dfrac{45}{8}=111\)
=\(\dfrac{11}{7}\)x\(\dfrac{37}{11}\)x\(\dfrac{56}{15}\)x\(\dfrac{45}{8}\)
=\(\dfrac{37}{7}\)x21
= 111