a) \(\left(-3\right)^2+3^3-\left(-3\right)^0\)
\(=9+27-1\)
\(=36-1\)
\(=35\)
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Thực hiện phép tính:1, left(dfrac{-1}{2}right)^2.left|+8right|-left(-dfrac{1}{2}right)^3:left|-dfrac{1}{16}right|2, left|-0,25right|-left(-dfrac{3}{2}right)^2:dfrac{1}{4}+dfrac{3}{4}.2017^03, left|dfrac{2}{3}-dfrac{5}{6}right|.left(3,6:2dfrac{2}{5}right)^34, left|left(-0,5right)^2+dfrac{7}{2}right|.10-left(dfrac{29}{30}-dfrac{7}{15}right):left(-dfrac{2017}{2018}right)^05, dfrac{8}{3}+left(3-dfrac{1}{2}right)^2-left|dfrac{-7}{3}right|
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Thực hiện phép tính:
1, \(\left(\dfrac{-1}{2}\right)^2.\left|+8\right|-\left(-\dfrac{1}{2}\right)^3:\left|-\dfrac{1}{16}\right|\)
2, \(\left|-0,25\right|-\left(-\dfrac{3}{2}\right)^2:\dfrac{1}{4}+\dfrac{3}{4}.2017^0\)
3, \(\left|\dfrac{2}{3}-\dfrac{5}{6}\right|.\left(3,6:2\dfrac{2}{5}\right)^3\)
4, \(\left|\left(-0,5\right)^2+\dfrac{7}{2}\right|.10-\left(\dfrac{29}{30}-\dfrac{7}{15}\right):\left(-\dfrac{2017}{2018}\right)^0\)
5, \(\dfrac{8}{3}+\left(3-\dfrac{1}{2}\right)^2-\left|\dfrac{-7}{3}\right|\)
21 tháng 4 2021 lúc 22:11
1.Tính nhanh
A =( \(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\)) x \(\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
2.Tìm n ∈ Z để \(\dfrac{n+3}{n-2}\)nhận giá trị nguyên
Bài 7 : Thực hiện phép tính :
a ) 5 - \(\left(-\frac{5}{11}\right)^0+\left(\frac{1}{3}\right)^2:3\)
b ) \(2^3+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^3:\frac{1}{2}\right]\)
a,3-left(frac{-6}{7}right)^0+left(frac{1}{2}right)^2:2b,left(-2right)^3+2^2+left(-1right)^{20}+left(-2right)^0c,left(left(3right)^2right)^2-left(left(-5right)^2right)^2-left(left(-2right)^3right)^2d,2^4+8[left(-2right)^2:frac{1}{2}]^0-2^{-2}.4+left(-2right)^2e, 2^3+3left(frac{1}{2}right)^0-2^{-2}.4+[left(-2right)^2:frac{1}{2}].8
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a,\(3-\left(\frac{-6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
b,\(\left(-2\right)^3+2^2+\left(-1\right)^{20}+\left(-2\right)^0\)
c,\(\left(\left(3\right)^2\right)^2-\left(\left(-5\right)^2\right)^2-\left(\left(-2\right)^3\right)^2\)
d,\(2^4+8[\left(-2\right)^2:\frac{1}{2}]^0-2^{-2}.4+\left(-2\right)^2\)
e, \(2^3+3\left(\frac{1}{2}\right)^0-2^{-2}.4+[\left(-2\right)^2:\frac{1}{2}].8\)
Bài 1: Thực hiện phép tính
a) \(2^3+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2:\frac{1}{2}\right]\)
b) \(\frac{2^{15}.9^4}{6^6.8^3}\)
c) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
d) \(\left(\frac{-10}{3}\right)^3.\left(\frac{-6}{5}\right)^4\)
Tính giá trị của biểu thức:Adfrac{-3}{7}.dfrac{5}{9}+dfrac{4}{9}.dfrac{-3}{7}+left(-2022right)^0B0,75-left(2dfrac{1}{3}+0,75right)+3^2.left(-dfrac{1}{9}right)C2dfrac{6}{7}.left[left(dfrac{-7}{5}-dfrac{3}{2}:dfrac{-5}{-4}right)+left(dfrac{3}{2}right)^2right]Ddfrac{2}{7}+dfrac{5}{7}.left(dfrac{3}{5}-0,25right).left(-2right)^2+35%E1dfrac{13}{15}.0,75-left(dfrac{11}{20}+25%right):1dfrac{2}{5}Fdfrac{dfrac{5}{3}-dfrac{5}{7}+dfrac{5}{9}}{dfrac{10}{3}-dfrac{10}{7}+dfrac{10}{9}}
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Tính giá trị của biểu thức:
\(A=\dfrac{-3}{7}.\dfrac{5}{9}+\dfrac{4}{9}.\dfrac{-3}{7}+\left(-2022\right)^0\)
\(B=0,75-\left(2\dfrac{1}{3}+0,75\right)+3^2.\left(-\dfrac{1}{9}\right)\)
\(C=2\dfrac{6}{7}.\left[\left(\dfrac{-7}{5}-\dfrac{3}{2}:\dfrac{-5}{-4}\right)+\left(\dfrac{3}{2}\right)^2\right]\)
\(D=\dfrac{2}{7}+\dfrac{5}{7}.\left(\dfrac{3}{5}-0,25\right).\left(-2\right)^2+35\%\)
\(E=1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):1\dfrac{2}{5}\)
\(F=\dfrac{\dfrac{5}{3}-\dfrac{5}{7}+\dfrac{5}{9}}{\dfrac{10}{3}-\dfrac{10}{7}+\dfrac{10}{9}}\)
27 tháng 8 2023 lúc 20:19
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)
15 tháng 1 2023 lúc 12:15
1. \(\left(1-x\right)^2+\left(3-y\right)^2+\left(y^2-x-z\right)^2=0\)
2. \(\left(x-y+z^2\right)+\left(y-2\right)^2+\left(z+3\right)^2=0\)
Làm hộ mình 2 câu này
Bài 1: Tính sau đó rút ra kết luận:left(-frac{1}{2}right)^3, left(-frac{1}{2}right)^2, left(-frac{1}{3}right)^4, left(-frac{1}{3}right)^5Bài 2: Tính:left(-frac{1}{4}right)^0, left(-2frac{1}{3}right)^2, left(-1frac{1}{3}right)^4
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Bài 1: Tính sau đó rút ra kết luận:
\(\left(-\frac{1}{2}\right)^3,\) \(\left(-\frac{1}{2}\right)^2,\) \(\left(-\frac{1}{3}\right)^4,\) \(\left(-\frac{1}{3}\right)^5\)
Bài 2: Tính:
\(\left(-\frac{1}{4}\right)^0,\) \(\left(-2\frac{1}{3}\right)^2,\) \(\left(-1\frac{1}{3}\right)^4\)