\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Rightarrow7\left(37-x\right)=3\left(x+13\right)\)
\(\Rightarrow259-7x=3x+39\)
\(\Rightarrow3x+7x=259-39\)
\(\Rightarrow10x=220\)
\(\Rightarrow x=22\)
đề bài=> 7(37-x)=3(x+13)
=>259-7x = 3x+39
=> 259-39 =3x+7x
=>220=10x
=>x=22
37−x/x+13 =37
⇒7(37−x)=3(x+13)
⇒259−7x=3x+39
⇒3x+7x=259−39
⇒10x=220
⇒x=22