Question

1. TÌM x biết :

\(\frac{2x+1}{x-3}+\frac{3-2x}{x+1}=0.\)

Answer 1

<=>\(\frac{\left(2x+1\right).\left(x+1\right)}{\left(x-3\right).\left(x+1\right)}\)+\(\frac{\left(3-2x\right).\left(x-3\right)}{\left(x+1\right).\left(x-3\right)}\)=0

<=>\(\frac{2x^2+3x+1}{\left(x-3\right).\left(x+1\right)}\)+\(\frac{3x-9-2x^2+6x}{\left(x+1\right).\left(x-3\right)}\)=0

<=>\(\frac{2x^2+3x+1+3x-9-2x^2+6x}{\left(x-3\right).\left(x+1\right)}\)=0

<=>\(\frac{12x-8}{\left(x-3\right).\left(x+1\right)}\)=0

=> 12x-8=0

=>x=2/3