Question

1) Tìm x a.2√x=1/3. b.2√x >3 2)Tìm điều kiện xác định a.√x+1/x-2; b.2/√(x+1)(x-2)

Answer 1

Ai giúp mình với 

Answer 2

Ai giải giúp mình đi mà😭

Answer 3

`1)`

a.\(2\sqrt{x}=\dfrac{1}{3}\)

\(ĐK:x\ge0\)

\(\Leftrightarrow\sqrt{x}=\dfrac{1}{6}\)
\(\Leftrightarrow x=\dfrac{1}{36}\) (tm)

Vậy \(S=\left\{\dfrac{1}{36}\right\}\)

b.\(2\sqrt{x}>3\)

\(ĐK:x\ge0\)

\(\Leftrightarrow\sqrt{x}>\dfrac{3}{2}\)

\(\Leftrightarrow x>\dfrac{9}{4}\)

Vậy \(S=\left\{x|x>\dfrac{9}{4}\right\}\)

`2)`

a.\(\dfrac{\sqrt{x}+1}{x-2}\)

\(ĐK:x\ge0\)

       \(x-2\ne0\Rightarrow x\ne2\)

b.\(\dfrac{2}{\sqrt{\left(x+1\right)\left(x-1\right)}}\)

\(\Leftrightarrow\dfrac{2}{\sqrt{x^2-1}}\)

\(ĐK:x^2-1\ge0\)

        \(\Leftrightarrow x^2\ge1\)

        \(\Leftrightarrow\left[{}\begin{matrix}x\ge1\\x\le-1\end{matrix}\right.\)