Question

1. Tìm STN n 

a. 2ⁿ=16

b. 4²ⁿ⁺¹=64

c. 6ⁿx 243= 1458

Answer 1

chào tiên

Answer 2

2ⁿ=16=>2ⁿ=2⁴=>n=4

\(4^{2n+1}=64\Rightarrow4^{2n+1}=4^3\)

\(\Rightarrow2n+1=4\Rightarrow n=\frac{3}{2}\)

c)\(6^n=6\Rightarrow n=1\)

k cho mk nha

Answer 3

a) 2ⁿ = 16

<=> 2ⁿ = 2⁴

<=> n = 4

b) 2²ⁿ⁺¹ = 64

<=> 2²ⁿ⁺¹ = 2⁶

<=> 2n+1 = 6

2n = 6 - 1

2n = 5

n = 5 :2

n = \(\frac{5}{2}\)

c) 6ⁿ . 243 = 1458

6ⁿ = 1485 : 243

6ⁿ = \(\frac{55}{9}\)

=> n vô hợp lý

Answer 4

a) 2ⁿ = 16

=> 2⁴ = 16

=> n = 4

b) 4²ⁿ⁺¹ = 64

=> 4²ⁿ⁺¹ = 4³

=> 2n + 1 = 4 

=> 2n = 3

=> n = 3/2

c) 6ⁿ . 243 = 1458

=> 6ⁿ = 6

=> n = 1

Answer 5

a

\(2^n\)=\(16\)\(\Rightarrow\)\(2^n\)=\(4^2\)\(\Rightarrow\)\(n=2\)

b.

\(4^{2n+1}=16\)

\(\Rightarrow\)\(4^{2n+1}=4^2\)

\(\Rightarrow\)\(2n+1=2\)

\(\Rightarrow\)\(2n=2-1\)

\(\Rightarrow\)\(2n=1\)

\(\Rightarrow n=1:2\)\(=\frac{1}{2}\)(câu này mình làm ko biết đúng ko nữa)

c

\(6^n\times243=1458\)

\(\Rightarrow6^n=1458\div243\)

\(6^n=6\)\(\Rightarrow6^n=6^1\Rightarrow n=1\)