Question

1 Tìm số nguyên \(x\)và \(y\),biết

\(\frac{3}{x}=\frac{y}{35}=\frac{-36}{84}\)

Answer 1

Ta có: \(\frac{-36}{84}=\frac{-3}{7}\)

\(\frac{3}{x}=\frac{-3}{7}\Rightarrow x=\frac{3.7}{-3}=-7\)

\(\frac{y}{35}=\frac{-3}{7}\Rightarrow y=\frac{\left(-3\right).35}{7}=-15\)

Vậy x = -7; y = -15

Answer 2

Ta có: \(\frac{-36}{84}=\frac{-3}{7}\)

\(\frac{3}{x}=\frac{-3}{7}\Rightarrow x=\frac{3.7}{-3}=-7\)

\(\frac{y}{35}=\frac{-3}{7}\Rightarrow y=\frac{\left(-3\right).35}{7}=-15\)

Vậy \(x=-7;y=-15\)

Answer 3

\(\frac{3}{x}=\frac{y}{35}=-\frac{36}{84}\)

\(+,\frac{3}{x}=-\frac{36}{84}\Rightarrow252=-36x\Rightarrow-7\)

\(+,\frac{y}{35}=-\frac{36}{84}\Rightarrow84y=-1260\Rightarrow-15\)

Answer 4

+)Ta có:\(\frac{-36}{84}=\frac{-3}{7}\)

\(\frac{3}{x}=\frac{-3}{7}\)

\(\Rightarrow3.7=-3x\)

\(\Rightarrow x=3.7:\left(-3\right)\)

\(\Rightarrow x=-7\)

\(\frac{y}{35}=\frac{-3}{7}\)

\(\Rightarrow\left(-3\right).35=7y\)

\(\Rightarrow y=\left(-3\right).35:7\)

\(\Rightarrow y=-15\)

Vậy \(\left(x,y\right)=\left[\left(-7\right);\left(-15\right)\right]\)

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