\(A=-2x^2+8x-15\)
\(A=-2\left(x^2-4x+\frac{15}{2}\right)\)
\(A=-2\left(x^2-2.x.2+4+\frac{7}{2}\right)\)
\(A=-2\left(\left(x-2\right)^2+\frac{7}{2}\right)\)
\(A=-7-2\left(x-2\right)^2\le-7\)
Vậy MAX A = -7 <=> x - 2 = 0 => x =2
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