Question

1 Tìm các số nguyên n để (4n+3):(n-2)

2 Tìm các số nguyên x,y sao cho xy+5 x+y+10=0

3 Tìm số nguyên n để (2n^2 +n-3):(n+1)

Answer 1

I don't now

mik ko biết 

sorry 

......................

Answer 2

1)\(4n+3⋮n-2\)

\(\Leftrightarrow4n+3=4\left(n-2\right)+11\)

\(\Rightarrow4\left(n-2\right)⋮n-2\)\(\Rightarrow n-2⋮n-2\)

\(\Rightarrow11⋮n-2\)

\(\Rightarrow n-2\in\left\{\pm1;\pm11\right\}\)

\(\Rightarrow n\in\left\{3;1;13;-9\right\}\)

2)\(xy+5x+y+10=0\)

\(\Leftrightarrow x\left(y+5\right)+y+5+5=0\)

\(\Leftrightarrow x\left(y+5\right)+\left(y+5\right)=-5\)

\(\Leftrightarrow\left(x+1\right).\left(y+5\right)=-5\)

x+1	-1	-5	1	5
y+5	5	1	-5	-1
x	-2	-6	0	4
y	0	-4	-10	-6

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