1. ST1= 1/20
ST2 = 1/5
2. C = 7/2; S = 3/4
1. ST1= 1/20
ST2 = 1/5
2. C = 7/2; S = 3/4
tim chieu dai va chieu rong cua hinh chu nhat co dien tich 12cm2 nhung co chu vi be nhat biet rang so do chieu dai va chieu rong deu la so tu nhien voi don vi xang ti met
1. Tim chu vi cua hinh chu nhat, biet rang neu tang chieu rong them 3m va chieu dai them 3m thi dien tich tang them 219m2.
2. Tim hai so biet tong cua chung bang 68 va 2/3 so lon thi bang 3/4 so be.
tim chieu dai va chieu rong cua hinh chu nhat co dien tich 12cm2 nhung co chu vi be nhat biet rang so do chieu dai va chieu rong deu la so tu nhien voi don vi xang-ti-met
MOT SAN VAN DONG HINH CHU NHAT CO CHIEU DAI 180M , CHIEU RONG BANG NUA CHIEU DAI . TINH CHU VI VA DIEN TICH CUA SAN VAN DONG DO
GIUP MINH VOI MINH DANG CAN GAP
cho mot hinh chu nhat co dien tich bang 360 m vuong . tinh dien tich hinh chu nhat co so do chieu dai va chieu rong bang 3/2 so do chieu dai va chieu rong cua hinh chu nhat da cho
Tinh chu vi va dien tich cua san hinh chu nhat biet 1/3 chieu dai cua san la 24 m va chieu rong cua san bang 3/4 chieu dai
cho 1 hinh chu nhat co dien tich bang 24cm vuong tang chieu rong them 2 phan3 so do do dai cua no va giu nguyen chieu dai thi duoc mot hcn moi tinh dien tich hcn au khi mo rong
bai 1 ; tuoi cua anh va tuoi cua em cong lai la 34 tuoi . Anh hon em 6 tuoi . Tinh tuoi cua moi nguoi
bai 2 ; mot thua ruong hinh chu nhat co chu nvi la 360 m , chieu rong be hon chieu dai la 20m . Tinh dien tich thua ruong
bai 3 ; tong cua hai so chan la 45 . Tim hai so do , biet rang giua chung chi co 5 so le
bafi 4 ; tong cua cac chu so cua mot so co hai chu so bang 11 . Neu thay doi thu tu cua cac chu so thi da cho tang them 27 don vi . Tim so do
giai ho minh nhe
chieu dai hon chieu rong 12 m. Ti so giua chieu rong va chieu dai la 4/7.
a) Tinh chieu dai, chieu rong cua hinh chu nhat do
b) tinh dien tich