1. So sánh
M = \(\frac{1}{1\cdot2}+\frac{1}{3\cdot4}+...+\frac{1}{37\cdot38}\) và N = \(\frac{1}{20}+\frac{1}{21}+...+\frac{1}{38}\)
2. Cho :
S = \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)
P = \(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\)
Tìm ( S - P )2013
cho S=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)
va P=\(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2012}+\frac{1}{2013}\)
tinh (S-P)2013
Cho \(S=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\) và \(P=\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2012}+\frac{1}{2013}\). Tính \(\left(S-P\right)^{2013}\)
\(S=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)
Và \(P=\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2012}+\frac{1}{2013}\)
Tính \(\left(S-P\right)^{2013}\)
Cho S=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)
P=\(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2012}+\frac{1}{2013}\)
Tinh \(\left(S-P\right)^{2013}\)
s=1-\(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)
và p=\(\frac{1}{1007}+\frac{1}{1008}+....+\frac{1}{2012}+\frac{1}{2013}\)
tính(S-P)^2013
đề thi chọn học sinh giỏi môn toán, lớp 7, tỉnh bắc giang năm học 2012-2013
Cho \(S=1-\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\) và \(P=\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2012}+\frac{1}{2013}\)
Tính ( S - P )2013
cho S=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)và P=\(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\)
Tính (S-P)213
Câu 1: Rút gọn: \(A=\left(\frac{3}{2}-\frac{2}{5}+\frac{1}{10}\right):\left(\frac{3}{2}-\frac{2}{3}+\frac{1}{12}\right)\)
Câu 2: Cho \(S=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)và \(P=\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2012}+\frac{1}{2013}\). Tính \(\left(S-P\right)^{2013}\)
Cho S=\(1-\frac{1}{2}+\frac{1}{3}\)-\(\frac{1}{4}\)+...........+\(\frac{1}{2011}\)-\(\frac{1}{2012}\)+\(\frac{1}{2013}\)và P=\(\frac{1}{1007}\)+\(\frac{1}{1008}\)+.....+\(\frac{1}{2012}\)+\(\frac{1}{2013}\)
Tính \(\left(S-P\right)^{2013}\)
