\(\frac{x}{5}=\frac{y}{-3}\) áp dụng t/c dãy TSBN =>\(\frac{x}{5}=\frac{y}{-3}=\frac{x^2+y}{5^2+\left(-3\right)}=\frac{34}{22}=\frac{17}{11}\)
\(\frac{x^2}{5^2}=\frac{17}{11}\Rightarrow x=....\)
\(\frac{y}{-3}=\frac{17}{11}\Rightarrow y=...\) cậu tự lm nhé
2) đặt \(\frac{x}{4}=\frac{y}{5}=k\) ta có \(\hept{\begin{cases}x=4k\\y=5k\\\end{cases}}\)\(\Rightarrow\)x.y=4k.5k=20
=> x.y=\(20.k^2\)=20
=>\(k^2\)=1=>k=1
=>x=4k=4.1=4
y=5k=5.1=5