| x - 2,4| = \(\dfrac{1}{2}\)
\(\left[{}\begin{matrix}x-2,4=\dfrac{1}{2}(đk:x>2,4)\\x-2,4=-\dfrac{1}{2}(đk:x< 2,4)\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{1}{2}+2,4\\x=-\dfrac{1}{2}+2,4\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2,9(tm)\\x=1,9(tm)\end{matrix}\right.\)
vậy \(x\in\) { 1,9 ; 2,9}
I x - 2,4 I = 1/2
I x - 12/5 I = 1/2
I x I = 1/2 + 12/5
I x I =29/10
x = 29/10
x= 1/2+2,4
x= 1/2+12/5
x= 5/10+14/10
x= 19/10
x= 1,9
Vậy x=1.9
⇒ \( x -2,4 = \dfrac{1}{2}\)
⇒ \(x\) \(=\) \( \dfrac{1}{2}+2,4\)
⇒ \(x\) \(= \) \(2,9\)
\(hoặc \)
⇒\( x-2,4=-\dfrac{1}{2}\)
⇒\(x \) \(=\) \(-\dfrac{1}{2}+2,4\)
⇒\(x\) \(=1,9\)
\(|x-2,4|=\dfrac{1}{2}\)
x-2,4=\(\dfrac{1}{2}\) hoặc x-2,4=-\(\dfrac{1}{2}\)
x =\(\dfrac{1}{2}\)+2,4 hoặc x = -\(\dfrac{1}{2}\)+2,4
x =\(\dfrac{29}{10}\) hoặc x =\(\dfrac{19}{10}\)
|x- 2,4| =\(\dfrac{1}{2}\)
=> x- 2,4= \(\dfrac{1}{2}\) hoặc \(\dfrac{-1}{2}\)
Ta có: x- 2,4= \(\dfrac{1}{2}\) => x= \(\dfrac{1}{2}\)+ 2,4= 2,9
x- 2,4=\(\dfrac{-1}{2}\)=> x= \(\dfrac{-1}{2}\)+ 2,4= 1,9
=> x= 2,9 hoặc 1,9
