vì x;y;z tỉ lệ với 5;4;3
=>x/5=y/4=z/3
=>x=5k;y=4k;z=3k
=>Y=(x+2y-3z)/(x-2y+3z)=(5k+8k-9k)/(5k-8k+9k)=(4k)/(6k)=2/3
Theo bài ra ta có: \(\frac{x}{5}\)=\(\frac{y}{4}\)=\(\frac{z}{3}\)= k
\(\Rightarrow\) x=5k, y=4k, z=3k
P=\(\frac{5k+8k-9k}{5k-8k+9k}\)=\(\frac{4k}{6k}\)= \(\frac{2}{3}\)
Vậy P=\(\frac{2}{3}\)
Vì x;y;z tỉ lệ với 5;4;3
\(\Rightarrow\)\(\frac{x}{5}\)= \(\frac{y}{4}\)= \(\frac{z}{3}\)
\(\Rightarrow\) x=5k; y=4k; z=3k
Thay vào P ta được:
P = \(\frac{x+2y-3z}{x-2y+3z}\)
\(\Leftrightarrow\)P = \(\frac{5k+2.4k-3.3k}{5k-2.4k+3.3k}\)
\(\Leftrightarrow\) P = \(\frac{5k+8k-9k}{5k-8k+9k}\)
\(\Leftrightarrow\) P = \(\frac{\left(5+8-9\right)k}{\left(5-8+9\right)k}\)
\(\Leftrightarrow\) P = \(\frac{4k}{6k}\)
\(\Leftrightarrow\) P = \(\frac{4}{6}\)= \(\frac{2}{3}\)