1)
A= \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{39.40}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-...+\frac{1}{39}-\frac{1}{40}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{40}\)
=> A= 27/120
A = \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{39.40}\)
= \(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{39}-\frac{1}{40}\)
= \(\frac{1}{3}-\frac{1}{40}\)
= \(\frac{37}{120}\)
B = \(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{37.40}\)
= \(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
= \(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{40}\right)\)
= \(\frac{1}{3}.\frac{9}{40}=\frac{3}{40}\)
C = \(\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{37.40}\)
= \(\frac{2}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
= \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{40}\right)\)
= \(\frac{2}{3}.\frac{9}{40}=\frac{3}{20}\)
1) A = \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{39.40}\)
A = \(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{39}-\frac{1}{40}\)
A = \(\frac{1}{3}-\frac{1}{40}\)
A = \(\frac{37}{120}\)
2) B = \(\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{7}\right)+\frac{1}{3}.\left(\frac{1}{7}-\frac{1}{10}\right)+...+\frac{1}{3}.\left(\frac{1}{37}-\frac{1}{40}\right)\)
B = \(\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
B = \(\frac{1}{3}.\frac{9}{40}\)
B = \(\frac{3}{40}\)
3) C = \(\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{37.40}\)
C = \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{7}\right)+\frac{2}{3}.\left(\frac{1}{7}-\frac{1}{10}\right)+...+\frac{2}{3}.\left(\frac{1}{37}-\frac{1}{40}\right)\)
C = \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
C = \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{40}\right)\)
C = \(\frac{2}{3}.\frac{9}{40}\)
C = \(\frac{3}{20}\)
suy ra A = 1/3-1/4+1/4-1/5+....+1/39-1/40
= 1/3 - 1/40
= 37/120
3B = 3/4.7+3/7.10+....+3/39.40
= 1/4 -1/7+1/7-1/10+....+1/39-1/40
= 1/4 - 1/40
= 9/40
B = 9/40 : 3 = 3/40
3/2.C = 3/4.7+3/7.10+....+3/39.40
= 1/4 -1/7+1/7-1/10+....+1/39-1/40
= 1/4 - 1/40
= 9/40
C = 9/40 : 3/2 = 3/20
tích mk nha, cách làm đúng 100% đó, nếu muốn chắc chắn thì bn có thể tính lại mấy phép tính cuối
nhớ tích đó, cảm ơn trước!!!! hihi