\(1+\dfrac{4}{5}+\dfrac{7}{6}+\dfrac{1}{5}=1+\dfrac{7}{6}+\left(\dfrac{4}{5}+\dfrac{1}{5}\right)=\dfrac{6+7}{6}+\dfrac{4+1}{5}=\dfrac{13}{6}+1=\dfrac{13+6}{6}=\dfrac{19}{6}\)
1+\(\dfrac{4}{5}+\dfrac{7}{6}+\dfrac{1}{5}\)
=(1+\(\dfrac{7}{^6}\))+\(\left(\dfrac{4}{5}+\dfrac{1}{5}\right)\)
= \(\dfrac{13}{6}+1\)
=\(\dfrac{19}{6}\)