\(\dfrac{1-2x}{-5}=\dfrac{-5}{1-2x}\left(x\ne\dfrac{1}{2}\right)\) \(\Rightarrow\left[{}\begin{matrix}1-2x=5\\1-2x=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\) Vậy ...
\(\dfrac{1-2x}{-5}=\dfrac{-5}{1-2x}\left(x\ne\dfrac{1}{2}\right)\) \(\Rightarrow\left[{}\begin{matrix}1-2x=5\\1-2x=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\) Vậy ...
1) (x + 1/2).(2/3 - 2x) = 0 2) 2/3x + 1/2x = 5/2 : 3 và 3/4 3) (2x - 3)(6 - 2x)= 0 4) -5(x + 1/5) - 1/2(x - 2/3) = 3/2x - 5/6
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
a,-2\3x+1\5=1\10
b,2|1\2x-3\8|-3\2=1\4
c,-5(x+1\5)-1\2(x-2\3)=3\2x-5\6
d,3(x-1\2)- 5(x+3\5)=-x+1\5
e,3\4-2.|2x-0,125|=2
f,2|1\2x-1\3|-3\2=1\4
g,4\5-1\2x=1\10
a/ 2.(1/2x -1/3)-3/2=1/4
b/ (1/2+2x)(2x-3)=0
c/ (4x-5)(5/4x-2)=0
d/ 1/4-(2x+1/2)mũ hai=0
Tìm x
a) 1/3x + 2/5( x - 1 ) = 0
b) (2x - 3 )(6 - 2x ) =0
c) 2|1/2x - 1/3 | - 3/2 = 1/4
d) 3/4 - 2 . | 2x - 2/3 | = 2
e) ( 3x - 1)(-1/2x + 5 ) = 0
g)-5(x + 1/5 ) - 1/2(x - 2/3 ) = 2/3x - 5/6
h) 3(x - 1/2 ) - 5(x + 3/5 ) = -3 + 1/5
i) 60%x + 2/3x = 1/3. 6và1/3 ( 6và1/3 là hỗn số )
1/3×5 +1/5×7 +.......+1/2x+1×2x+3=15/93
Tìm x bt 2x/ 1 × 3 + 2x/ 3 x 5 + 2x / 5 x 7 +...+2x/2011×2013
1,Tìm x
5^x-5^x+2=650
2x-3/11+2x-4/12+2x-5/13=2x-6/14+2x-7/15+2x-8/6