\(\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)...\left(1-\dfrac{1}{9}\right)\)
\(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot...\cdot\dfrac{8}{9}\)
\(=\dfrac{1\cdot2\cdot3\cdot...\cdot8}{2\cdot3\cdot4\cdot...\cdot9}\)
\(=\dfrac{1}{9}\)
1. a,23/27-(11/17-4/27) +(28/17) b,2/3 .7/9 +2/3 .2/9-2/9 c,7/3:5/11-1/3.11/5 d,(1+1/2) .(1+1/3) .(1+1/4).......(1+1/2023) e, (1-1/2).(1-1/3).....(1-1/2023) f,13/17.5/11-7/13.2/5+5/11.4/17-2/5.6/13 g, 1/2+1/3.1/4-1/5:1/6 2,so sánh n+2/n+3 và n+1/n+2 ( n là số tự nhiên)
1-1/2 ; 1/2-1/3 ; 1/3-1/4 ; 1/4-1/5 ; 1/5-1/6 ; 1/7-1/8 ; 1/8-1/9 ; 1/9-1/10
[9-(1/2+1/3+1/4+...1/10)]:(1/2+2/3+3/4+..+9/10)
CHO A=17+1/2+2/3+4/5+5/6+4/7+3/8+2/9+1/10 và
B=1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9+1/10
a) -5/9 . 4/13+ -5/9. 9/13+2 và 5/9 ( 2 và 5/9 là hỗn số)
b) (-2)^3. -1/24+( 4/3- 1 và 5/6) : 3/14
c) 200 - (-100) -100+ (-20)
d) 15/34 +7/21 +19/34 -5/15 +3/7
e) (1-1/2) . (1-1/3). (1-1/4).....(1-1/1012)
g) (1/2+1/3-1/4) : 7/24
h) 15^20 . 9^10/ 27^12.25^10
1) Tính: A= 2/4.7-3/5.9+2/7.10-3/9.13+..+2/301.304-3/401.405
2) Chứng minh rằng với mọi n thuộc số tự nhiên, n lớn hơn hoặc bằng 2: 3/9.14+3/14.19+...+3/(5n-1).(5n+4)<1/15
3) a) Cho A=9/5^2+9/11^2+9/17^2+...+9/305^2. Chứng minh A<3/4
b) Cho C=4/3+7/3^2+10/3^3+...+3n+1/3^n với số tự nhiên khác 0. Chứng minh rằng C<11/4
4) Tính: a) =1/2+1/2^2+1/2^3+...+1/2^100
b) B=1/3-1/3^2+1/3^3-1/3^4+...+1/3^99-1/3^100
5) So sánh: (1-1/2).(1-1/3).(1-1/4). ... .(1-1/20) với 1/21
S=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}>\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}...+\dfrac{1}{9.10}\)
=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}>\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}>\dfrac{1}{2}-\dfrac{1}{10}\)
=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}>\dfrac{2}{5}\)
S=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}< \dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{8.9}\)
=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}< 1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{8}-\dfrac{1}{9}\)
=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9}< 1-\dfrac{1}{9}\)
=\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{9^2}< \dfrac{8}{9}\)
Vậy \(\dfrac{2}{5}< S< \dfrac{8}{9}\)
1/1*2+1/2*3+1/3*4+1/4*5+1/5*6+1/6*7+1/7*8+1/8*9+1/9*10
b1: th phép tính a. 10/11 : 19/22 + 9/11 : 19/22 b. 20/9 . 84 - 2/9 . 84 c. (1/2 - 1/3) . (5 - 1/4) d. (1/2 - 1/3 - 1/6) . (3/202 + 4/203 + 5/204) b2: th phép tính a. 4 3/8 + 5 2/3 ( hỗn số) b. 2 3/8 + 1 1/4 + 3 6/7 (hỗn số) c. 2 3/8 - 1 1/4 + 5 1/3 (hỗn số) d. 3 5/6 + 2 1/6 . 6 (hỗn số) e. 3 1/2 + 4 5/7 - 5 5/14 (hỗn số) f. 4 1/2 + 1/2 : 5 1/2 (hỗn số) giúp với ạ
[9-(1/2+1/3+1/4+......+1/10)]:[1/2+2/3+3/4+.........+9/10].toán lớp 6
