\(1\frac{1}{10}-\frac{3}{4}\)
\(=\frac{11}{10}-\frac{3}{4}\)
\(=\frac{7}{20}\)
\(\frac{11}{10}-\frac{3}{4}=\frac{7}{20}\)
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\(1\frac{1}{10}-\frac{3}{4}=\frac{11}{10}-\frac{3}{4}\)
\(=\frac{22}{20}-\frac{15}{20}\)
\(=\frac{7}{20}\)
\(\frac{11}{10}-\frac{3}{4}\)
\(\frac{11}{10}=\frac{11\times4}{10\times4}=\frac{44}{40}\)
\(\frac{3}{4}=\frac{3\times10}{4\times10}=\frac{30}{40}\)
Vậy \(\frac{44}{40}-\frac{30}{40}=\frac{14}{40}\) thì \(\frac{11}{10}-\frac{3}{4}=\frac{14}{40}=\frac{7}{20}\)