Tính từ từ là ra ^^
= \(-1,1:\left(-3\right)+\frac{1}{3}-\frac{-1}{12}\)
= \(\frac{11}{30}+\frac{1}{3}+\frac{1}{12}\)( Mẫu chung: 60 )
= \(\frac{22}{60}\)+ \(\frac{20}{60}\)+ \(\frac{5}{60}\)
= \(\frac{47}{60}\)
Bạn làm cho mình 1 con nữa nhé
2\(^3\)+3.(\(\frac{1^0}{2}\))-1+[(-2)\(^2\):\(\frac{1}{2}\)].8
\(2^3+3\cdot\left(\frac{1}{2}\right)^0-1+\left[\left(-2\right)^2:\frac{1}{2}\right]\cdot8\)
\(=8+3\cdot1-1+\left(4:\frac{1}{2}\right)\cdot8\)
\(=8+3-1+8\cdot8\)
\(=8+3-1+64\)
\(=11-1+64\)
\(=10+64\)
\(=74\)