\(0,3\left(18\right)=0,3+0,0\left(18\right)=\frac{3}{10}+\frac{1}{10}.0,\left(18\right)=\frac{3}{10}+\frac{1}{10}.18.0,\left(01\right)=\frac{3}{10}+\frac{1}{10}.18.\frac{1}{99}=\frac{7}{22}\)
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