a. \(\overline{t}\) =\(\frac{1,553+1,549+1,556}{3}\) ≈ 1,553s⇒ Đ
b. Δt2 = \(\left\vert1,549-1,553\right\vert\) = 0,004s ⇒ S
c. \(\overline{\Delta t}\) = \(\frac{\left\vert1,553-1,553\right\vert+0,004+\left\vert1.553-1.556\right\vert}{3}\) ≈ 0,0023s ⇒ S
d. t = 1,5530 ± 0,0023 ⇒ S

