\(P=\left(x^2-4xy+4y^2\right)+y^2-4x+2y+15\)
\(=\left(x-2y\right)^2-4\left(x-2y\right)+4+\left(y^2-6y+9\right)+2\)
\(=\left(x-2y-2\right)^2+\left(y-3\right)^2+2\ge2\)
Dấu "=" xảy ra khi \(\begin{cases}x-2y-2=0\\ y-3=0\end{cases}\)
\(\Rightarrow\begin{cases}x=8\\ y=3\end{cases}\)
Khi đó \(M=\left(8-9\right)^{2024}+\left(3-2\right)^{2025}=1+1=2\)

