Đặt \(sin\left(x-\dfrac{\Omega}{3}\right)=a\left(a\in\left[-1;1\right]\right)\)
Phương trình sẽ trở thành \(a^2-a=0\)
=>a(a-1)=0
=>\(\left[{}\begin{matrix}a=0\\a=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}sin\left(x-\dfrac{\Omega}{3}\right)=0\\sin\left(x-\dfrac{\Omega}{3}\right)=1\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x-\dfrac{\Omega}{3}=k\Omega\\x-\dfrac{\Omega}{3}=\dfrac{\Omega}{2}+k2\Omega\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\Omega}{3}+k\Omega\\x=\dfrac{5}{6}\Omega+k2\Omega\end{matrix}\right.\)
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