`5x^5 =x^3`
`=> 5x^5-x^3=0`
`=> x^3 ( 5x^2-1)=0`
\(\Rightarrow\left[{}\begin{matrix}x^3=0\\5x^2-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\5x^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x^2=\dfrac{1}{5}\left(ktm\right)\end{matrix}\right.\)
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\(\left(2x-3\right)^3=64\\ \Rightarrow\left(2x-3\right)^3=4^3\\ \Rightarrow2x-3=4\\ \Rightarrow2x=4+3\\ \Rightarrow2x=7\\ \Rightarrow x=\dfrac{7}{2}\left(ktm\right)\)
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`(5x-1)^2 =2023^0 . 7 +3^2`
`=> (5x-1)^2 =1. 7 +9`
`=> (5x-1)^2 =7+9`
`=> (5x-1)^2 =16`
`=> (5x-1)^2 = (+- 4)^2`
\(\Rightarrow\left[{}\begin{matrix}5x-1=4\\5x-1=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x=5\\5x=-3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{3}{5}\left(ktm\right)\end{matrix}\right.\)
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KTM ( Không thỏa mãn ) vì `x` là số tự nhiên.
